Class 8 Maths Practice Paper
CBSE · Olympiad Style · 20 MCQ Questions · Answer Key Included
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Class 8 Maths Practice Paper

Algebra, Mensuration & Data Handling · CBSE · Olympiad Style
📝 20 Questions 🎯 MCQ Format ✅ Answer Key Included 🖨 Print Ready (A4) 🆓 Free
A
Arjun Sharma's Practice Paper
🏏 Cricket fan 🚀 Space enthusiast 👁️ Visual learner CBSE Class 8

Mathematics — Class 8 Practice Paper

Algebra, Mensuration & Data Handling
📋 Board: CBSE 📚 Class: 8 ⏱ Time: 60 minutes 🏆 Max Marks: 80 ❓ Questions: 20
Instructions: All questions are compulsory. Each question carries 4 marks. There is no negative marking. Choose the most appropriate option.
Q1.
Factorise: x² − 9
A) (x+3)(x+3)
B) (x−3)(x−3)
C) (x+3)(x−3)
D) (x+9)(x−1)
Q2.
Volume of a cube with side 6 cm:
A) 36 cm³
B) 108 cm³
C) 216 cm³
D) 252 cm³
Q3.
Arjun's compound interest on ₹8,000 at 10% per annum for 2 years?
A) ₹1,600
B) ₹1,640
C) ₹1,680
D) ₹1,720
Q4.
(a + b)² = ?
A) a² + b²
B) a² + 2ab + b²
C) a² − 2ab + b²
D) a² + ab + b²
Q5.
Curved surface area of cylinder: r=7 cm, h=10 cm (π=22/7):
A) 220 cm²
B) 440 cm²
C) 550 cm²
D) 660 cm²
Q6.
Solve: (2x − 5)(x + 3) = 0. Solutions?
A) x = 5, x = −3
B) x = 5/2, x = −3
C) x = −5/2, x = 3
D) x = 2/5, x = 3
Q7.
Median of: 3, 7, 12, 5, 9, 1, 14
A) 5
B) 7
C) 9
D) 12
Q8.
ISRO cylindrical fuel tank: r=3.5 m, h=12 m. Volume? (π=22/7)
A) 154 m³
B) 308 m³
C) 462 m³
D) 616 m³
Q9.
If P(x) = 2x³ − 3x + 1, find P(1):
A) 0
B) 1
C) 2
D) 3
Q10.
Profit% formula:
A) (Profit/SP)×100
B) (Profit/CP)×100
C) (SP−MRP)/CP×100
D) (CP−SP)/CP×100
Q11.
Arjun buys cricket gear for ₹4,500, sells at ₹5,400. Profit%?
A) 15%
B) 18%
C) 20%
D) 25%
Q12.
Expand: (3x − 2y)²
A) 9x² − 4y²
B) 9x² + 4y²
C) 9x² − 12xy + 4y²
D) 9x² + 12xy − 4y²
Q13.
Total surface area of cube with side 5 cm:
A) 25 cm²
B) 50 cm²
C) 125 cm²
D) 150 cm²
Q14.
Mode of: 4, 7, 4, 3, 8, 4, 7, 9, 7, 4
A) 4
B) 7
C) 4 and 7
D) 3
Q15.
Factorise: 6x² + 11x + 3
A) (2x+3)(3x+1)
B) (6x+1)(x+3)
C) (3x+3)(2x+1)
D) (2x+1)(3x+3)
Q16.
Simple interest on ₹6,000 at 8% per annum for 3 years:
A) ₹1,200
B) ₹1,320
C) ₹1,440
D) ₹1,560
Q17.
Range of: 23, 45, 12, 67, 34, 78, 19
A) 56
B) 60
C) 64
D) 66
Q18.
x² − 5x + 6 = 0. Roots are:
A) 2, 3
B) −2, −3
C) 1, 6
D) −1, 6
Q19.
Volume of sphere: r = 21 cm (π=22/7):
A) 9702 cm³
B) 38,808 cm³
C) 77,616 cm³
D) 1,386 cm³
Q20.
Probability that a number chosen from 1-20 is prime:
A) 2/5
B) 7/20
C) 3/5
D) 3/10
✅ Answer Key & Solutions
Q1 C Difference of squares: x² − 3² = (x+3)(x−3)
Q2 C V = 6³ = 216 cm³
Q3 C A = 8000(1.1)² = 8000×1.21 = 9680; CI = 9680−8000 = ₹1680
Q4 B (a+b)² = a² + 2ab + b²
Q5 B CSA = 2πrh = 2 × 22/7 × 7 × 10 = 440 cm²
Q6 B 2x−5=0 → x=5/2; x+3=0 → x=−3
Q7 B Sorted: 1,3,5,7,9,12,14; median (4th term) = 7
Q8 C V = πr²h = 22/7 × 3.5² × 12 = 22/7 × 12.25 × 12 = 462 m³
Q9 A P(1) = 2(1)³ − 3(1) + 1 = 2 − 3 + 1 = 0
Q10 B Profit% = (Profit/Cost Price) × 100
Q11 C Profit = 900; 900/4500 × 100 = 20%
Q12 C (a−b)² = a²−2ab+b² → 9x²−12xy+4y²
Q13 D TSA = 6a² = 6 × 25 = 150 cm²
Q14 A 4 appears 4 times; 7 appears 3 times. Mode = 4
Q15 A 6x²+9x+2x+3 = 3x(2x+3)+1(2x+3) = (2x+3)(3x+1)
Q16 C SI = (6000×8×3)/100 = ₹1440
Q17 D Range = Max − Min = 78 − 12 = 66
Q18 A (x−2)(x−3) = 0 → x = 2 or x = 3
Q19 B V = 4/3πr³ = 4/3 × 22/7 × 9261 = 38,808 cm³
Q20 A Primes 1-20: 2,3,5,7,11,13,17,19 = 8 primes; P = 8/20 = 2/5

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