✅ Answer Key & Solutions
Q1
B
√5 cannot be expressed as p/q; it is irrational
Q2
C
AB = √[(5-2)²+(7-3)²] = √[9+16] = √25 = 5
Q3
A
a³−b³=(a−b)(a²+ab+b²); 27x³−8y³=(3x−2y)(9x²+6xy+4y²)
Q4
B
1 − 3 + 3 − 1 = 0
Q5
B
1/7 = 0.142857142857... (repeating block of 6 digits)
Q6
D
Remainder = p(2) = 8 + 12 − 10 + 2 = 12
Q7
B
x=0 means the point lies on the y-axis
Q8
A
At x=0: y = 3(0)+2 = 2. Point = (0, 2)
Q9
B
√49 = 7, √64 = 8; so √50 lies between 7 and 8
Q10
B
x²+y² = (x+y)² − 2xy = 49 − 24 = 25
Q11
A
3.66 × 22 ≈ 80.52 m² ≈ 8.052 × 10¹
Q12
A
x² − 5x + 6 = (x−2)(x−3) = 0 → x = 2, 3
Q13
A
Multiply by (√5−√3)/(√5−√3): = (√5−√3)/(5−3) = (√5−√3)/2
Q14
C
Both negative → Quadrant III
Q15
B
(a+b)(a−b) = a²−b² = 4x²−9
Q16
A
r is remainder; 0 ≤ r < b
Q17
C
0 × √2 = 0 (rational); 2 × √3 = 2√3 (irrational). It depends — but non-zero rational × irrational = irrational
Q18
B
156=132×1+24; 132=24×5+12; 24=12×2+0. HCF=12
Q19
D
Number of zeroes = number of points where graph cuts/touches x-axis = 3
Q20
C
√(−4) is imaginary/complex, not real
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